To go from anhydrous to the decahydrate (i.e. 10 H20) you need to use the following calculation: 285.99 x (weight required / 105.99). The different forms have different crystal structures and so have more of less water associated with them. Once dissolved they are identical but you need to take account of the amount of water in the crystals. The molecular weight of anhydrous Na2CO3 105.99 and so to calculate how much of any hydrated form is required you need you adjust the weight required by the ratio of the weight of the hydrated form to the anhydrous form. Above is for the decahydrate, i.e. 105.99 + (10 x 18 [molecular weight of water]); so for the monohydrate it would be 105.99 + 18 and for the heptahydrate 105.99 + (7 x 18).